There is a line that includes the point (–5,–8) and has a slope of –10. What is its equation in point-slope form?

Answer 1

The point-slope form of a linear equation is given by the formula:

\[ y - y_1 = m(x - x_1) \]

where \( m \) is the slope of the line, and \( (x_1, y_1) \) is a point on the line.

Given the point \( (-5, -8) \) and the slope \( m = -10 \), we can substitute these values into the formula:

\[ y - (-8) = -10(x - (-5)) \]

This simplifies to:

\[ y + 8 = -10(x + 5) \]

So the equation of the line in point-slope form is:

\[ y + 8 = -10(x + 5) \]