A line with a slope of –5 passes through the point (–4,–8). What is its equation in point-slope form?

Answer 1

To write the equation of a line in point-slope form, you can use the formula:

$$y-y_1=m(x-x_1)$$

where $m$ is the slope and $(x_1,y_1)$ is a point on the line.

Given:

• Slope $m=-5$
• Point $(x_1,y_1)=(-4,-8)$

Substituting these values into the formula:

$$y-(-8)=-5(x-(-4))$$

This simplifies to:

$$y+8=-5(x+4)$$

So, the equation of the line in point-slope form is:

$$y+8=-5(x+4)$$