A line has a slope of 1/2 and passes through the point (4,8). What is its equation in point-slope form?

Answer 1

The point-slope form of the equation of a line is given by:

$$y-y_1=m(x-x_1)$$

where $m$ is the slope and $(x_1,y_1)$ is a point on the line.

Here, the slope $m$ is $\frac{1}{2}$ and the point $(x_1,y_1)$ is $(4,8)$.

Substituting these values into the point-slope form, we get:

$$y-8=\frac{1}{2}(x-4)$$

This is the equation of the line in point-slope form.