Question
Circle 1 has a central angle
θ
and a radius of 9 inches. The angle intercepts an arc length of 6 inches.
Circle 2 has the same central angle
θ
as Circle 1, but a radius of 3 inches.
image
What is the arc length of Circle 2?
A.
2 in
B.
3 in
C.
6 in
D.
9 in
θ
and a radius of 9 inches. The angle intercepts an arc length of 6 inches.
Circle 2 has the same central angle
θ
as Circle 1, but a radius of 3 inches.
image
What is the arc length of Circle 2?
A.
2 in
B.
3 in
C.
6 in
D.
9 in
Answers
Answered by
GPT-4o mini
To find the arc length of Circle 2, we can use the relationship between arc length, radius, and central angle. The formula for arc length \( L \) is given by:
\[
L = r \theta
\]
where \( r \) is the radius and \( \theta \) is the central angle in radians.
From Circle 1, we know that:
- The radius \( r_1 = 9 \) inches.
- The arc length \( L_1 = 6 \) inches.
Using the formula for Circle 1, we can solve for \( \theta \):
\[
6 = 9 \theta
\]
To find \( \theta \):
\[
\theta = \frac{6}{9} = \frac{2}{3} \text{ radians}
\]
Now we can use this value of \( \theta \) to find the arc length of Circle 2, which has a radius \( r_2 = 3 \) inches.
Using the same formula for Circle 2:
\[
L_2 = r_2 \theta = 3 \cdot \frac{2}{3} = 2 \text{ inches}
\]
Therefore, the arc length of Circle 2 is:
\[
\boxed{2 \text{ in}}
\]
\[
L = r \theta
\]
where \( r \) is the radius and \( \theta \) is the central angle in radians.
From Circle 1, we know that:
- The radius \( r_1 = 9 \) inches.
- The arc length \( L_1 = 6 \) inches.
Using the formula for Circle 1, we can solve for \( \theta \):
\[
6 = 9 \theta
\]
To find \( \theta \):
\[
\theta = \frac{6}{9} = \frac{2}{3} \text{ radians}
\]
Now we can use this value of \( \theta \) to find the arc length of Circle 2, which has a radius \( r_2 = 3 \) inches.
Using the same formula for Circle 2:
\[
L_2 = r_2 \theta = 3 \cdot \frac{2}{3} = 2 \text{ inches}
\]
Therefore, the arc length of Circle 2 is:
\[
\boxed{2 \text{ in}}
\]