There is a line that includes the point (–8,6) and has a slope of 1/10

. What is its equation in point-slope form?

1 answer

The point-slope form of a line is given by the equation:

\[ y - y_1 = m(x - x_1) \]

where \( (x_1, y_1) \) is a point on the line and \( m \) is the slope.

Given the point \( (–8, 6) \) where \( x_1 = -8 \) and \( y_1 = 6 \), and the slope \( m = \frac{1}{10} \), we can substitute these values into the point-slope form equation:

\[ y - 6 = \frac{1}{10}(x - (-8)) \]

This simplifies to:

\[ y - 6 = \frac{1}{10}(x + 8) \]

So, the equation of the line in point-slope form is:

\[ y - 6 = \frac{1}{10}(x + 8) \]