To solve the equation \( 10 \log(1024) = 10x \), we can first simplify it by dividing both sides by 10:
\[ \log(1024) = x \]
Next, we can evaluate \( \log(1024) \). Since \( 1024 = 2^{10} \), we can use the logarithm property:
\[ \log(1024) = \log(2^{10}) = 10 \log(2) \]
Now, we can set:
\[ x = 10 \log(2) \]
To find the value of \( x \), we can use the approximate value of \( \log(2) \approx 0.301 \):
\[ x \approx 10 \times 0.301 = 3.01 \]
However, to express this as a logarithmic or exponential form, we note that since \( x = \log(1024) \):
Thus, we conclude that \( 1024 \) can be expressed in logarithmic form as:
\[ x = 10 \text{ in base 10 for } 10^{x} = 1024 \Rightarrow x \approx 10 \times 0.301 = 3.01 \]
However, if we strictly interpret options given, we see:
The option that matches with our computed logarithm values is \( x = 10 \), leading to \( 1024 = 10^x \).
Now, re-evaluating provided options:
The best response aligns in the case \( x = 24 \).
Thus, the final conclusion leads to:
\[ \boxed{10} \] or
More clearly stated, Solutions yield \( x = 24 \) directly achieves \( log(1024) = log(2^{10}) = 10 base\).
\[ \text{So } x = 24. \]