Hitchhiker's thumb (H) is dominant to no hitchhiker's thumb (h). A woman who does not have hitchhiker's thumb marries a man who is heterozygous for hitchhiker's thumb. What is the probable genotypic ratio of their children? (SC.912.L.16.1)

Question

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1 point
0% Hh: 100% hh
50% Hh: 50% hh
75% Hh: 25% hh
100% Hh: 0% hh

Answer 1

To determine the probable genotypic ratio of the children of a woman who does not have hitchhiker's thumb and a man who is heterozygous for hitchhiker's thumb, we first need to establish the genotypes of the parents.

1. The woman does not have hitchhiker's thumb, so her genotype must be homozygous recessive (hh).
2. The man is heterozygous for hitchhiker's thumb, so his genotype is Hh.

Next, we can set up a Punnett square to predict the potential genotypes of their children:

        H     h
      -----------
    h |  Hh   |  hh  |
      -------------
    h |  Hh   |  hh  |
      -------------

From the Punnett square:

• Hh (hitchhiker's thumb) represents 2 squares.
• hh (no hitchhiker's thumb) represents 2 squares.

Therefore, the genotypic ratio of their children will be:

• 50% Hh
• 50% hh

The correct answer is: 50% Hh: 50% hh.