To determine how many push-ups Dean needs to do each remaining day to reach his goal of more than 900 push-ups, we can establish the inequality as follows:
Part A: Create an Inequality
Let \( x \) be the number of push-ups Dean must do each remaining day.
He has already completed 230 push-ups, and he has 20 days left. Therefore, the total number of push-ups he will complete can be represented by:
\[ 230 + 20x > 900 \]
This is the inequality representing the number of push-ups Dean needs to do.
Part B: Solve for Minimum Push-ups per Day
Now, we need to solve the inequality for \( x \):
-
Subtract 230 from both sides:
\[ 20x > 900 - 230 \]
\[ 20x > 670 \]
-
Divide both sides by 20:
\[ x > \frac{670}{20} \]
\[ x > 33.5 \]
Since he needs to do a whole number of push-ups, Dean must do at least 34 push-ups each day to satisfy the inequality.
Therefore, the minimum number of push-ups Dean must do on each remaining day is:
Part B Answer: 34 push-ups