Given f, of, x, equals, minus, 4, x, squared, plus, 3, x, minus, 11f(x)=−4x

Question

2
+3x−11, find f, of, minus, 4f(−4)

Answer 1

To find \( f(-4) \) for the function \( f(x) = -4x^2 + 3x - 11 \), we start by substituting \(-4\) into the function.

\[ f(-4) = -4(-4)^2 + 3(-4) - 11 \]

Calculating each term step-by-step:

1. Calculate \((-4)^2\): \[ (-4)^2 = 16 \]

2. Multiply by \(-4\): \[ -4 \cdot 16 = -64 \]

3. Calculate \(3(-4)\): \[ 3 \cdot (-4) = -12 \]

Now substitute these values back into \( f(-4) \):

\[ f(-4) = -64 - 12 - 11 \]

Combine the values:

\[ f(-4) = -64 - 12 = -76 \] \[ f(-4) = -76 - 11 = -87 \]

Thus, \( f(-4) = -87 \).

Now, we need to find \( -4f(-4) \):

\[ -4f(-4) = -4(-87) = 348 \]

Therefore, the final answer is:

\[ \boxed{348} \]