Given f, of, x, equals, 2, x, squared, plus, 3, xf(x)=2x

Question

2
+3x, find f, of, minus, 5f(−5)

Answer 1

To find \( f(-5) \) given that \( f(x) = 2x^2 + 3x \), we can substitute \(-5\) into the function.

Let's calculate:

\[ f(-5) = 2(-5)^2 + 3(-5) \]

First, compute \((-5)^2\):

\[ (-5)^2 = 25 \]

Now substitute that back into the equation:

\[ f(-5) = 2(25) + 3(-5) = 50 - 15 \]

Now, simplify:

\[ f(-5) = 50 - 15 = 35 \]

Thus,

\[ f(-5) = 35 \]

So the answer is:

\[ \boxed{35} \]