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A soccer player kicks a ball, applying a force of 1,000 newtons over a distance of 0.2 meter. The ball travels 50 meters down t...Asked by kitty
a soccer player kicks a ball, applying a force of 1,000 newtons over a distance of 0.2 meter. the ball travels 50 meters down the field before another player stops the ball. how much work was done during the kick?
answers:
5,000 joules
10 joules
50,000 joules
200 joules
answers:
5,000 joules
10 joules
50,000 joules
200 joules
Answers
Answered by
GPT-4o mini
To calculate the work done during the kick, we can use the formula for work:
\[
\text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta)
\]
where:
- Work is measured in joules (J),
- Force is measured in newtons (N),
- Distance is measured in meters (m),
- \(\theta\) is the angle between the force and the direction of motion.
In this case, we assume the kick is directly in the direction of the ball's motion, so \(\theta = 0\) degrees (and \(\cos(0) = 1\)).
Given:
- Force = 1000 N
- Distance = 0.2 m
Now we can calculate the work done:
\[
\text{Work} = 1000 \, \text{N} \times 0.2 \, \text{m} \times \cos(0)
\]
\[
\text{Work} = 1000 \times 0.2 \times 1 = 200 \, \text{joules}
\]
So, the amount of work done during the kick is **200 joules**.
\[
\text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta)
\]
where:
- Work is measured in joules (J),
- Force is measured in newtons (N),
- Distance is measured in meters (m),
- \(\theta\) is the angle between the force and the direction of motion.
In this case, we assume the kick is directly in the direction of the ball's motion, so \(\theta = 0\) degrees (and \(\cos(0) = 1\)).
Given:
- Force = 1000 N
- Distance = 0.2 m
Now we can calculate the work done:
\[
\text{Work} = 1000 \, \text{N} \times 0.2 \, \text{m} \times \cos(0)
\]
\[
\text{Work} = 1000 \times 0.2 \times 1 = 200 \, \text{joules}
\]
So, the amount of work done during the kick is **200 joules**.
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