To find the electric current in each circuit, we can use Ohm's Law, which states:
\[ I = \frac{V}{R} \]
where \( I \) is the current, \( V \) is the voltage, and \( R \) is the resistance.
Let's calculate the current for each circuit:
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Circuit 1:
- Resistance \( R_1 = 0.5 \) ohms
- Voltage \( V_1 = 20 \) volts
- Current \( I_1 = \frac{20}{0.5} = 40 \) amperes
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Circuit 2:
- Resistance \( R_2 = 0.5 \) ohms
- Voltage \( V_2 = 40 \) volts
- Current \( I_2 = \frac{40}{0.5} = 80 \) amperes
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Circuit 3:
- Resistance \( R_3 = 0.25 \) ohms
- Voltage \( V_3 = 40 \) volts
- Current \( I_3 = \frac{40}{0.25} = 160 \) amperes
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Circuit 4:
- Resistance \( R_4 = 0.25 \) ohms
- Voltage \( V_4 = 60 \) volts
- Current \( I_4 = \frac{60}{0.25} = 240 \) amperes
Now let's compare the currents:
- Circuit 1: 40 A
- Circuit 2: 80 A
- Circuit 3: 160 A
- Circuit 4: 240 A
Conclusion: Circuit 4 has the greatest electric current, which is 240 amperes.