Reed is snorkeling on the surface of the ocean, 22 feet from an anchored boat. The anchor is on the ocean floor, 34 feet away from Reed. What is the angle of depression between Reed and the anchor?(1 point)

Responses

40°
40 degrees

50°
50 degrees

65°
65 degrees

90°

1 answer

To find the angle of depression between Reed and the anchor, we can use the information given to visualize a right triangle. In this triangle:

  • The distance from Reed to the boat (22 feet) is one leg of the triangle (horizontal leg).
  • The distance from the boat to the anchor (34 feet) is the hypotenuse.
  • The vertical distance from the surface of the ocean to the anchor can be calculated using the Pythagorean theorem.

First, let's denote:

  • \(a = 22\) feet (horizontal distance from Reed to the boat),
  • \(c = 34\) feet (hypotenuse from the surface to the anchor).

We can find the vertical distance \(b\) (depth to the anchor) using the Pythagorean theorem: \[ a^2 + b^2 = c^2 \] \[ 22^2 + b^2 = 34^2 \] \[ 484 + b^2 = 1156 \] \[ b^2 = 1156 - 484 \] \[ b^2 = 672 \] \[ b = \sqrt{672} \approx 25.9 \text{ feet} \]

Now, we want to find the angle of depression. The angle of depression \(θ\) can be calculated using the tangent function: \[ \tan(θ) = \frac{\text{opposite}}{\text{adjacent}} = \frac{b}{a} \] So, \[ \tan(θ) = \frac{25.9}{22} \]

Calculating this: \[ \tan(θ) \approx 1.176 \]

Now, to find the angle \(θ\): \[ θ = \tan^{-1}(1.176) \approx 50.2° \]

Hence, rounding to the nearest whole number, the angle of depression is approximately 50°.

Therefore, the answer is: 50°