Question

IJ
is dilated by a scale factor of start fraction, 3, divided by, 4, end fraction
4
3
​
to form start overline, I, prime, J, prime, end overline
I
′
J
′

. start overline, I, J, end overline
IJ
measures 4040. What is the measure of start overline, I, prime, J, prime, end overline
I
′
J
′

?

Answer 1

To find the measure of \( \overline{I'J'} \) after dilation, you can use the formula:

\[
\text{New Length} = \text{Original Length} \times \text{Scale Factor}
\]

Given that the original length \( \overline{IJ} = 4040 \) and the scale factor is \( \frac{3}{4} \), you can substitute values into the formula:

\[
\overline{I'J'} = 4040 \times \frac{3}{4}
\]

Now, perform the calculation:

\[
\overline{I'J'} = 4040 \times \frac{3}{4} = 4040 \times 0.75 = 3030
\]

Thus, the measure of \( \overline{I'J'} \) is \( 3030 \).