Question
Write a system of equations to describe the situation below, solve using elimination, and fill in the blanks.
An employee at a party store is assembling balloon bouquets. For a graduation party, he assembled 6 small balloon bouquets and 3 large balloon bouquets, which used a total of 126 balloons. Then, for a Father's Day celebration, he used 246 balloons to assemble 7 small balloon bouquets and 8 large balloon bouquets. How many balloons are in each bouquet?
An employee at a party store is assembling balloon bouquets. For a graduation party, he assembled 6 small balloon bouquets and 3 large balloon bouquets, which used a total of 126 balloons. Then, for a Father's Day celebration, he used 246 balloons to assemble 7 small balloon bouquets and 8 large balloon bouquets. How many balloons are in each bouquet?
Answers
Answered by
GPT-4o mini
Let \( x \) represent the number of balloons in a small bouquet, and \( y \) represent the number of balloons in a large bouquet. We can set up a system of equations based on the information provided:
From the graduation party, where 6 small and 3 large bouquets use a total of 126 balloons, we have the equation:
\[
6x + 3y = 126
\]
From the Father's Day celebration, where 7 small and 8 large bouquets use a total of 246 balloons, we have the second equation:
\[
7x + 8y = 246
\]
Now we can simplify the first equation. Divide all terms in the first equation by 3:
\[
2x + y = 42 \quad \text{(Equation 1)}
\]
Now we write the second equation as it is:
\[
7x + 8y = 246 \quad \text{(Equation 2)}
\]
Next, we can use the elimination method to solve this system of equations. First, we will express \( y \) from Equation 1:
From Equation 1:
\[
y = 42 - 2x \quad \text{(Substituting for y)}
\]
Now substitute \( y \) in Equation 2:
\[
7x + 8(42 - 2x) = 246
\]
Distribute \( 8 \):
\[
7x + 336 - 16x = 246
\]
Combine like terms:
\[
-9x + 336 = 246
\]
Now, subtract 336 from both sides:
\[
-9x = 246 - 336
\]
\[
-9x = -90
\]
Dividing both sides by -9 gives:
\[
x = 10
\]
Now substitute \( x = 10 \) back into the expression for \( y \):
\[
y = 42 - 2(10)
\]
\[
y = 42 - 20
\]
\[
y = 22
\]
Thus, the number of balloons in each bouquet is:
- Small bouquet: **10 balloons**
- Large bouquet: **22 balloons**
To summarize:
\[
\boxed{10} \text{ for small bouquets and } \boxed{22} \text{ for large bouquets.}
\]
From the graduation party, where 6 small and 3 large bouquets use a total of 126 balloons, we have the equation:
\[
6x + 3y = 126
\]
From the Father's Day celebration, where 7 small and 8 large bouquets use a total of 246 balloons, we have the second equation:
\[
7x + 8y = 246
\]
Now we can simplify the first equation. Divide all terms in the first equation by 3:
\[
2x + y = 42 \quad \text{(Equation 1)}
\]
Now we write the second equation as it is:
\[
7x + 8y = 246 \quad \text{(Equation 2)}
\]
Next, we can use the elimination method to solve this system of equations. First, we will express \( y \) from Equation 1:
From Equation 1:
\[
y = 42 - 2x \quad \text{(Substituting for y)}
\]
Now substitute \( y \) in Equation 2:
\[
7x + 8(42 - 2x) = 246
\]
Distribute \( 8 \):
\[
7x + 336 - 16x = 246
\]
Combine like terms:
\[
-9x + 336 = 246
\]
Now, subtract 336 from both sides:
\[
-9x = 246 - 336
\]
\[
-9x = -90
\]
Dividing both sides by -9 gives:
\[
x = 10
\]
Now substitute \( x = 10 \) back into the expression for \( y \):
\[
y = 42 - 2(10)
\]
\[
y = 42 - 20
\]
\[
y = 22
\]
Thus, the number of balloons in each bouquet is:
- Small bouquet: **10 balloons**
- Large bouquet: **22 balloons**
To summarize:
\[
\boxed{10} \text{ for small bouquets and } \boxed{22} \text{ for large bouquets.}
\]
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