Question

What is the probability of parents with allele combinations Ff and FF having an offspring that is FF?

50%

100%

75%

25%

Answer 1

To determine the probability of parents with allele combinations Ff (heterozygous) and FF (homozygous dominant) having an offspring that is FF, we can set up a simple Punnett square.

The alleles of the first parent (Ff) can contribute either F or f, while the alleles of the second parent (FF) can only contribute F. Here is how the combinations would work out:

- Parent 1 (Ff) can contribute: F or f
- Parent 2 (FF) can contribute: F

The possible combinations of alleles in the offspring are:

1. F from Ff (Parent 1) + F from FF (Parent 2) = FF
2. f from Ff (Parent 1) + F from FF (Parent 2) = Ff

Thus, the possible genotypes for the offspring are:
- FF (from the first combination)
- Ff (from the second combination)

Now, let's analyze the combinations:

- 1 out of 2 offspring will be FF (50%)
- 1 out of 2 offspring will be Ff (50%)

Therefore, the probability of an offspring being FF is 50%.

The correct answer is:

**50%**