To analyze the situation, we can use Ohm's Law, which states that \( V = I \cdot R \), where \( V \) is voltage, \( I \) is current, and \( R \) is resistance.
Circuit A has a resistance of \( R_A = 7.5 , \Omega \) and Circuit B has a resistance of \( R_B = 5 , \Omega \).
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If the current in circuit A is less than the current in circuit B:
- Let \( I_A < I_B \).
- Voltage in circuit A: \( V_A = I_A \cdot R_A \)
- Voltage in circuit B: \( V_B = I_B \cdot R_B \)
- If \( I_A < I_B \) and knowing resitance, \( R_A > R_B \), we cannot conclude that \( V_A < V_B \).
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If the current in circuit A is equal to the current in circuit B:
- Let \( I_A = I_B \).
- Then \( V_A = I_A \cdot 7.5 \) and \( V_B = I_A \cdot 5 \).
- Since \( 7.5 > 5 \), it follows that \( V_A > V_B \).
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If the voltage of circuit A is equal to the voltage of circuit B:
- Here, \( V_A = V_B \).
- That means \( I_A \cdot 7.5 = I_B \cdot 5 \).
- Given that \( R_A > R_B \), this would require \( I_A < I_B \) for the voltages to remain equal.
Based on this analysis, the correct statement is:
- If the voltage of circuit A is equal to the voltage of circuit B, then the current in circuit A is less than the current in circuit B.
This is the only universally true statement given the values of resistance in the two circuits.