Question

Use the following formula to find the efficiency of energy transfer between the harbor seal (2,500 Kcal) and a polar bear (375 Kcal).

(Energy level transfered to next level)(Total energy input) × 100


(1 point)
Responses

12%
12%

15%
15%

20%
20%

10%

Answer 1

To find the efficiency of energy transfer, we can use the provided formula:

\[
\text{Efficiency} = \left( \frac{\text{Energy level transferred to next level}}{\text{Total energy input}} \right) \times 100
\]

In this case:
- Energy level transferred to the polar bear = 375 Kcal (the energy the polar bear receives from the harbor seal).
- Total energy input from the harbor seal = 2500 Kcal (the energy content of the harbor seal).

Now, we can plug the numbers into the formula:

\[
\text{Efficiency} = \left( \frac{375 \text{ Kcal}}{2500 \text{ Kcal}} \right) \times 100
\]

Calculating this:

1. Calculate the fraction:
\[
\frac{375}{2500} = 0.15
\]

2. Now multiply by 100 to get the percentage:
\[
0.15 \times 100 = 15\%
\]

Thus, the efficiency of energy transfer between the harbor seal and the polar bear is **15%**.