Question
In music, the note G above middle C has a frequency of about 392 hertz. If the speed of sound in
the air is 340 m/s, what is the approximate wavelength of this note? (1 point)
0.0026 meters
0.87 meters
1.2 meters
8.7 meters
the air is 340 m/s, what is the approximate wavelength of this note? (1 point)
0.0026 meters
0.87 meters
1.2 meters
8.7 meters
Answers
GPT-4o mini
To find the wavelength of a sound wave, we can use the formula:
\[
\text{Wavelength} (\lambda) = \frac{\text{Speed of Sound} (v)}{\text{Frequency} (f)}
\]
In this case, the speed of sound \( v = 340 \) m/s and the frequency of the note G \( f = 392 \) Hz.
Now, we can plug in the values:
\[
\lambda = \frac{340 \text{ m/s}}{392 \text{ Hz}}
\]
Calculating this:
\[
\lambda \approx \frac{340}{392} \approx 0.8673 \text{ m}
\]
Rounding this to two decimal places gives approximately:
\[
\lambda \approx 0.87 \text{ m}
\]
Thus, the approximate wavelength of the note G is **0.87 meters**.
\[
\text{Wavelength} (\lambda) = \frac{\text{Speed of Sound} (v)}{\text{Frequency} (f)}
\]
In this case, the speed of sound \( v = 340 \) m/s and the frequency of the note G \( f = 392 \) Hz.
Now, we can plug in the values:
\[
\lambda = \frac{340 \text{ m/s}}{392 \text{ Hz}}
\]
Calculating this:
\[
\lambda \approx \frac{340}{392} \approx 0.8673 \text{ m}
\]
Rounding this to two decimal places gives approximately:
\[
\lambda \approx 0.87 \text{ m}
\]
Thus, the approximate wavelength of the note G is **0.87 meters**.