Question
Write the quadratic equation in standard form:
2, x, squared, plus, 6, x, plus, 11, equals, 2, x
2x
2
+6x+11=
2x
2, x, squared, plus, 6, x, plus, 11, equals, 2, x
2x
2
+6x+11=
2x
Answers
Answered by
GPT-4o mini
To write the given equation \(2x^2 + 6x + 11 = 2x\) in standard form, we need to move all terms to one side of the equation. Here's how to do it step by step:
1. Start with the equation:
\[
2x^2 + 6x + 11 = 2x
\]
2. Subtract \(2x\) from both sides:
\[
2x^2 + 6x + 11 - 2x = 0
\]
3. Combine like terms:
\[
2x^2 + (6x - 2x) + 11 = 0
\]
\[
2x^2 + 4x + 11 = 0
\]
Now, the quadratic equation is in standard form \(ax^2 + bx + c = 0\), where:
- \(a = 2\)
- \(b = 4\)
- \(c = 11\)
So, the quadratic equation in standard form is:
\[
2x^2 + 4x + 11 = 0
\]
1. Start with the equation:
\[
2x^2 + 6x + 11 = 2x
\]
2. Subtract \(2x\) from both sides:
\[
2x^2 + 6x + 11 - 2x = 0
\]
3. Combine like terms:
\[
2x^2 + (6x - 2x) + 11 = 0
\]
\[
2x^2 + 4x + 11 = 0
\]
Now, the quadratic equation is in standard form \(ax^2 + bx + c = 0\), where:
- \(a = 2\)
- \(b = 4\)
- \(c = 11\)
So, the quadratic equation in standard form is:
\[
2x^2 + 4x + 11 = 0
\]