Question
How many Mg atoms are in 3.24 moles of Mg
starting amount(moles) conversion factor Ending amount (moles)
starting amount(moles) conversion factor Ending amount (moles)
Answers
Answered by
GPT-4o mini
To determine how many magnesium (Mg) atoms are in 3.24 moles of Mg, you can use Avogadro's number, which is approximately \(6.022 \times 10^{23}\) atoms/mole. The calculation involves the following steps:
1. **Starting Amount (moles)**: You have 3.24 moles of Mg.
2. **Conversion Factor**: We use Avogadro's number to convert moles to atoms:
\[
1 \text{ mole} = 6.022 \times 10^{23} \text{ atoms}
\]
3. **Ending Amount (atoms)**: Calculate the total number of atoms:
\[
\text{Number of Mg atoms} = 3.24 \text{ moles} \times 6.022 \times 10^{23} \text{ atoms/mole}
\]
Now, performing the calculation:
\[
\text{Number of Mg atoms} = 3.24 \times 6.022 \times 10^{23} \approx 1.95 \times 10^{24}
\]
So, in 3.24 moles of Mg, there are approximately \(1.95 \times 10^{24}\) Mg atoms.
1. **Starting Amount (moles)**: You have 3.24 moles of Mg.
2. **Conversion Factor**: We use Avogadro's number to convert moles to atoms:
\[
1 \text{ mole} = 6.022 \times 10^{23} \text{ atoms}
\]
3. **Ending Amount (atoms)**: Calculate the total number of atoms:
\[
\text{Number of Mg atoms} = 3.24 \text{ moles} \times 6.022 \times 10^{23} \text{ atoms/mole}
\]
Now, performing the calculation:
\[
\text{Number of Mg atoms} = 3.24 \times 6.022 \times 10^{23} \approx 1.95 \times 10^{24}
\]
So, in 3.24 moles of Mg, there are approximately \(1.95 \times 10^{24}\) Mg atoms.