To solve the inequality \( 4x - 8 \leq 4 \), we first isolate \( x \).
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Add 8 to both sides: \[ 4x - 8 + 8 \leq 4 + 8 \] \[ 4x \leq 12 \]
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Divide both sides by 4: \[ x \leq 3 \]
Now, we need to find the whole numbers less than 10 that satisfy \( x \leq 3 \). The whole numbers less than or equal to 3 that are also less than 10 are:
- 0
- 1
- 2
- 3
Thus, the solution is \( 0, 1, 2, 3 \).
The correct response is: 0, 1, 2, 3