Question

Brody is going to see a movie and is taking his 2 kids. Each movie ticket costs $13 and there are an assortment of snacks available to purchase for $5 each. How much total money would Brody have to pay for his family if he were to buy 4 snacks for everybody to share? How much would Brody have to pay if he bought x snacks for everybody to share?

Answer 1

To calculate the total amount of money Brody would have to pay for the movie tickets and the snacks:

1. **Cost of Movie Tickets:**
- Brody has 2 kids, so the total number of tickets is:
\[
\text{Total tickets} = 1 \text{ (for Brody)} + 2 \text{ (for the kids)} = 3
\]
- The cost of movie tickets is:
\[
\text{Total ticket cost} = 3 \text{ tickets} \times 13 \text{ dollars/ticket} = 39 \text{ dollars}
\]

2. **Cost of Snacks:**
- If Brody buys 4 snacks, the cost of the snacks is:
\[
\text{Total snack cost} = 4 \text{ snacks} \times 5 \text{ dollars/snack} = 20 \text{ dollars}
\]

3. **Total Cost if Buying 4 Snacks:**
- The total amount Brody would pay if he buys 4 snacks is:
\[
\text{Total cost} = \text{Total ticket cost} + \text{Total snack cost} = 39 \text{ dollars} + 20 \text{ dollars} = 59 \text{ dollars}
\]

Now, if Brody buys \( x \) snacks instead, the cost of the snacks would be:
\[
\text{Total snack cost} = x \text{ snacks} \times 5 \text{ dollars/snack} = 5x \text{ dollars}
\]

4. **Total Cost if Buying \( x \) Snacks:**
- The total amount Brody would pay if he buys \( x \) snacks is:
\[
\text{Total cost} = \text{Total ticket cost} + \text{Total snack cost} = 39 \text{ dollars} + 5x \text{ dollars} = 39 + 5x \text{ dollars}
\]

In summary:
- If Brody buys 4 snacks, he pays **59 dollars**.
- If he buys \( x \) snacks, he pays **\( 39 + 5x \) dollars**.