To determine which ordered pairs represent points on the graph of the equation \( y = 3x + 2 \), we can substitute the x-values from the ordered pairs into the equation and check if the corresponding y-values match.
Let's say we have the following ordered pairs to evaluate:
- \( (0, 2) \)
- \( (1, 5) \)
- \( (2, 8) \)
- \( (3, 11) \)
- \( (4, 14) \)
- \( (-1, -1) \)
Now let's evaluate each pair:
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For \( (0, 2) \): \[ y = 3(0) + 2 = 2 \] This matches, so \( (0, 2) \) is a point on the graph.
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For \( (1, 5) \): \[ y = 3(1) + 2 = 5 \] This matches, so \( (1, 5) \) is a point on the graph.
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For \( (2, 8) \): \[ y = 3(2) + 2 = 8 \] This matches, so \( (2, 8) \) is a point on the graph.
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For \( (3, 11) \): \[ y = 3(3) + 2 = 11 \] This matches, so \( (3, 11) \) is a point on the graph.
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For \( (4, 14) \): \[ y = 3(4) + 2 = 14 \] This matches, so \( (4, 14) \) is a point on the graph.
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For \( (-1, -1) \): \[ y = 3(-1) + 2 = -3 + 2 = -1 \] This matches, so \( (-1, -1) \) is a point on the graph.
Summary of ordered pairs that are on the graph of \( y = 3x + 2 \):
- \( (0, 2) \)
- \( (1, 5) \)
- \( (2, 8) \)
- \( (3, 11) \)
- \( (4, 14) \)
- \( (-1, -1) \)
Thus, all the given pairs are valid points on the graph of \( y = 3x + 2 \).