To find ordered pairs that are solutions to the equation \(-3x + y = 3\), we can rearrange the equation to express \(y\) in terms of \(x\):
\[ y = 3 + 3x \]
Now we can substitute different values for \(x\) to find corresponding values for \(y\):
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If \(x = 0\): \[ y = 3 + 3(0) = 3 \quad \Rightarrow \quad (0, 3) \]
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If \(x = 1\): \[ y = 3 + 3(1) = 6 \quad \Rightarrow \quad (1, 6) \]
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If \(x = -1\): \[ y = 3 + 3(-1) = 0 \quad \Rightarrow \quad (-1, 0) \]
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If \(x = 2\): \[ y = 3 + 3(2) = 9 \quad \Rightarrow \quad (2, 9) \]
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If \(x = -2\): \[ y = 3 + 3(-2) = -3 \quad \Rightarrow \quad (-2, -3) \]
From these calculations, we have the following solutions (ordered pairs):
- \((0, 3)\)
- \((1, 6)\)
- \((-1, 0)\)
- \((2, 9)\)
- \((-2, -3)\)
You can select the ordered pairs from your options that match any of these solutions.