Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
A circle is drawn on a coordinate plane with the center point at (-4, 6) and a radius of 2. Derive the equation of the circle f...Question
A circle is drawn on a coordinate plane with the center point at (0,3)
and a radius of 3. Derive the equation of the circle from the given information. Fill in the missing information in the following equation.(2 points)
(x−
)2+
(y−
)2=
and a radius of 3. Derive the equation of the circle from the given information. Fill in the missing information in the following equation.(2 points)
(x−
)2+
(y−
)2=
Answers
There are no human answers yet.
Answered by
GPT-4o mini
The equation of a circle in the coordinate plane can be expressed using the formula:
\[
(x - h)^2 + (y - k)^2 = r^2
\]
where \((h, k)\) is the center of the circle and \(r\) is the radius.
From the information given:
- The center of the circle is \((0, 3)\), so \(h = 0\) and \(k = 3\).
- The radius is \(3\), so \(r = 3\).
Now, substituting these values into the equation:
1. \(h = 0\)
2. \(k = 3\)
3. \(r^2 = 3^2 = 9\)
Putting it all together in the equation:
\[
(x - 0)^2 + (y - 3)^2 = 9
\]
So, filling in the missing information:
\[
(x - 0)^2 + (y - 3)^2 = 9
\]
Thus, the finalized equation is:
\[
(x - 0)^2 + (y - 3)^2 = 9
\]
\[
(x - h)^2 + (y - k)^2 = r^2
\]
where \((h, k)\) is the center of the circle and \(r\) is the radius.
From the information given:
- The center of the circle is \((0, 3)\), so \(h = 0\) and \(k = 3\).
- The radius is \(3\), so \(r = 3\).
Now, substituting these values into the equation:
1. \(h = 0\)
2. \(k = 3\)
3. \(r^2 = 3^2 = 9\)
Putting it all together in the equation:
\[
(x - 0)^2 + (y - 3)^2 = 9
\]
So, filling in the missing information:
\[
(x - 0)^2 + (y - 3)^2 = 9
\]
Thus, the finalized equation is:
\[
(x - 0)^2 + (y - 3)^2 = 9
\]
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.