To graph the linear equation \( y = 2x - 3 \), we'll identify two key points and then draw the line through them.
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Find the y-intercept (when \( x = 0 \)): \[ y = 2(0) - 3 = -3 \] So, the point is \( (0, -3) \).
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Choose another value for \( x \) to find a corresponding \( y \) value (let's use \( x = 1 \)): \[ y = 2(1) - 3 = 2 - 3 = -1 \] So, the point is \( (1, -1) \).
Now, we can plot these points on a graph:
- The point \( (0, -3) \) indicates where the line crosses the y-axis.
- The point \( (1, -1) \) gives us another point on the line.
- Draw the line: Connect the two points with a straight line and extend it with arrows on both ends.
Choosing from the provided descriptions, the correct graph should show a line that passes through the points \( (0, -3) \) and \( (1, -1) \), consistent with the equation \( y = 2x - 3 \).
None of the provided responses accurately described the correct graph of the equation \( y = 2x - 3 \), but based on our analysis, it should be a line passing through \( (0, -3) \) and \( (1, -1) \).