Asked by kymari davis-shanks
Solving Equations Using Substitution Quick Check
2 of 52 of 5 Items
Question
Solve the system of equations.
2x+6y=−18
x=5y−1
(1 point)
Responses
(4, 1)
left parenthesis 4 comma 1 right parenthesis
(5.25, 1.25)
left parenthesis 5.25 comma 1.25 right parenthesis
(−7.25, −1.25)
left parenthesis negative 7.25 comma negative 1.25 right parenthesis
(−6, −1)
2 of 52 of 5 Items
Question
Solve the system of equations.
2x+6y=−18
x=5y−1
(1 point)
Responses
(4, 1)
left parenthesis 4 comma 1 right parenthesis
(5.25, 1.25)
left parenthesis 5.25 comma 1.25 right parenthesis
(−7.25, −1.25)
left parenthesis negative 7.25 comma negative 1.25 right parenthesis
(−6, −1)
Answers
Answered by
GPT-4o mini
To solve the system of equations using substitution, we have the following equations:
1. \(2x + 6y = -18\) (Equation 1)
2. \(x = 5y - 1\) (Equation 2)
We can substitute Equation 2 (the expression for \(x\)) into Equation 1.
Substituting \(x = 5y - 1\) into Equation 1:
\[
2(5y - 1) + 6y = -18
\]
Now, distribute the 2:
\[
10y - 2 + 6y = -18
\]
Combining like terms:
\[
16y - 2 = -18
\]
Now, add 2 to both sides:
\[
16y = -16
\]
Divide by 16:
\[
y = -1
\]
Now that we have \(y\), we can substitute it back into Equation 2 to find \(x\):
\[
x = 5(-1) - 1
\]
\[
x = -5 - 1
\]
\[
x = -6
\]
Thus, the solution to the system of equations is \((-6, -1)\).
Comparing this with the given options, the correct response is:
**(−6, −1)**
1. \(2x + 6y = -18\) (Equation 1)
2. \(x = 5y - 1\) (Equation 2)
We can substitute Equation 2 (the expression for \(x\)) into Equation 1.
Substituting \(x = 5y - 1\) into Equation 1:
\[
2(5y - 1) + 6y = -18
\]
Now, distribute the 2:
\[
10y - 2 + 6y = -18
\]
Combining like terms:
\[
16y - 2 = -18
\]
Now, add 2 to both sides:
\[
16y = -16
\]
Divide by 16:
\[
y = -1
\]
Now that we have \(y\), we can substitute it back into Equation 2 to find \(x\):
\[
x = 5(-1) - 1
\]
\[
x = -5 - 1
\]
\[
x = -6
\]
Thus, the solution to the system of equations is \((-6, -1)\).
Comparing this with the given options, the correct response is:
**(−6, −1)**