To solve the system of equations using substitution, follow these steps:
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Start with the two equations: \[ 8x - 3y = -22 \quad (1) \] \[ y = 10 + 4x \quad (2) \]
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Substitute equation (2) into equation (1). This means you will replace \( y \) in equation (1) with \( 10 + 4x \): \[ 8x - 3(10 + 4x) = -22 \]
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Distribute \(-3\) in the equation: \[ 8x - 30 - 12x = -22 \]
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Combine like terms: \[ -4x - 30 = -22 \]
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Add 30 to both sides: \[ -4x = 8 \]
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Divide both sides by \(-4\): \[ x = -2 \]
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Now, substitute \( x = -2 \) back into equation (2) to find \( y \): \[ y = 10 + 4(-2) \] \[ y = 10 - 8 \] \[ y = 2 \]
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The solution to the system of equations is: \[ (x, y) = (-2, 2) \]
So, the final answer is: \[ (-2, 2) \]