To solve the system of equations using substitution, we can follow these steps:
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We have the equations: \[ x = 6y - 3 \quad \text{(1)} \] \[ 2x + 7y = 13 \quad \text{(2)} \]
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Substitute equation (1) into equation (2) for \(x\): \[ 2(6y - 3) + 7y = 13 \]
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Distribute the 2: \[ 12y - 6 + 7y = 13 \]
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Combine like terms: \[ 19y - 6 = 13 \]
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Add 6 to both sides: \[ 19y = 19 \]
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Divide by 19: \[ y = 1 \]
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Now substitute \(y = 1\) back into equation (1) to find \(x\): \[ x = 6(1) - 3 \] \[ x = 6 - 3 \] \[ x = 3 \]
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The solution to the system of equations is: \[ (x, y) = (3, 1) \]
Thus, the final answer is: \[ (3, 1) \]