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An illustration shows a coordinate plane with 4 quadrants. The x-axis ranges from negative 9 to 9 in one unit increments, and the y-axis ranges from negative 11 to 11 in one unit increments. A line is graphed on the plane. An upward slanting line passes through points plotted at left parenthesis 1 comma 5 right parenthesis and left parenthesis 2 comma 10 right parenthesis.
The graph shows the proportional relationship. Derive the equation of the line y=mx
through the origin.
(1 point)
y=
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An illustration shows a coordinate plane with 4 quadrants. The x-axis ranges from negative 9 to 9 in one unit increments, and the y-axis ranges from negative 11 to 11 in one unit increments. A line is graphed on the plane. An upward slanting line passes through points plotted at left parenthesis 1 comma 5 right parenthesis and left parenthesis 2 comma 10 right parenthesis.
The graph shows the proportional relationship. Derive the equation of the line y=mx
through the origin.
(1 point)
y=
Skip to navigation
Answers
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Answered by
GPT-4o mini
To derive the equation of the line in the form \( y = mx \), we need to determine the slope \( m \) of the line that passes through the origin and the given points \( (1, 5) \) and \( (2, 10) \).
First, we calculate the slope \( m \) using the two points. The formula for the slope between two points \((x_1, y_1)\) and \((x_2, y_2)\) is:
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
Using the points \( (1, 5) \) and \( (2, 10) \):
- \( x_1 = 1, y_1 = 5 \)
- \( x_2 = 2, y_2 = 10 \)
Substituting into the slope formula:
\[
m = \frac{10 - 5}{2 - 1} = \frac{5}{1} = 5
\]
Now that we have the slope \( m = 5 \), we write the equation of the line that passes through the origin (0,0), which is:
\[
y = mx = 5x
\]
Therefore, the equation of the line is:
\[
\boxed{5x}
\]
First, we calculate the slope \( m \) using the two points. The formula for the slope between two points \((x_1, y_1)\) and \((x_2, y_2)\) is:
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
Using the points \( (1, 5) \) and \( (2, 10) \):
- \( x_1 = 1, y_1 = 5 \)
- \( x_2 = 2, y_2 = 10 \)
Substituting into the slope formula:
\[
m = \frac{10 - 5}{2 - 1} = \frac{5}{1} = 5
\]
Now that we have the slope \( m = 5 \), we write the equation of the line that passes through the origin (0,0), which is:
\[
y = mx = 5x
\]
Therefore, the equation of the line is:
\[
\boxed{5x}
\]
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