Asked by Mark
An insurance sales representative selects 3 policies to review. The group of policies she can select from contains 8 life policies, 5 automobile policies, and 2 homeowner policies. Find the probability of selecting”
(a) All life policies
(b) Both homeowner policies
(c) All automobile policies
(d) 1of each policy
(e) 2 life policies and 1 automobile policy
(a) All life policies
(b) Both homeowner policies
(c) All automobile policies
(d) 1of each policy
(e) 2 life policies and 1 automobile policy
Answers
Answered by
PsyDAG
I will formulate one problem to indicate the process and leave the rest to you.
(a) 3 life policies.
First 8/15, second (no replacement) 7/14, third 6/13.
Final probability for all found by multiplying the individual probabilities.
This should give you a start.
(a) 3 life policies.
First 8/15, second (no replacement) 7/14, third 6/13.
Final probability for all found by multiplying the individual probabilities.
This should give you a start.
Answered by
ursula
a. 12/65
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