To calculate the volume of a cylindrical rain barrel, you can use the formula for the volume \( V \) of a cylinder:
\[ V = \pi r^2 h \]
Where:
- \( r \) is the radius of the cylinder,
- \( h \) is the height of the cylinder,
- \( \pi \) is approximately 3.14159.
First, we need to find the radius from the diameter. Given that the diameter is 22 inches, the radius \( r \) is:
\[ r = \frac{\text{diameter}}{2} = \frac{22}{2} = 11 \text{ inches} \]
Now we can substitute the radius and height into the volume formula:
\[ V = \pi (11)^2 (37) \]
Calculating \( (11)^2 \):
\[ (11)^2 = 121 \]
Now substitute back into the volume formula:
\[ V = \pi \times 121 \times 37 \]
Calculating \( 121 \times 37 \):
\[ 121 \times 37 = 4477 \]
Now plug this into the equation:
\[ V \approx 3.14159 \times 4477 \approx 14057.78 \]
Therefore, the volume of the rain barrel is approximately:
\[ 14,057.78 \text{ inches}^3 \]
The correct response is:
14,057.78 inches³