Question

Michelle just bought a 5−gallon
paint can. The paint bucket resembles a right circular cylinder. If the height is 15.6
inches, and the radius is 5.9
inches, what is the volume of the paint bucket? Use 3.14
for π
. Round to the nearest tenth.(1 point)
inches3

Answer 1

To calculate the volume of a right circular cylinder, we use the formula:

\[
V = \pi r^2 h
\]

where:
- \( V \) is the volume,
- \( r \) is the radius,
- \( h \) is the height,
- \( \pi \) is approximately 3.14.

Given:
- Height (\( h \)) = 15.6 inches
- Radius (\( r \)) = 5.9 inches
- \( \pi \) = 3.14

Now, substituting the values into the formula:

\[
V = 3.14 \times (5.9)^2 \times 15.6
\]

First, calculate \( (5.9)^2 \):

\[
(5.9)^2 = 34.81
\]

Next, substitute this value back into the volume formula:

\[
V = 3.14 \times 34.81 \times 15.6
\]

Now calculate \( 3.14 \times 34.81 \):

\[
3.14 \times 34.81 \approx 109.6
\]

Finally, multiply this result by 15.6:

\[
V \approx 109.6 \times 15.6 \approx 1714.56
\]

So, rounding to the nearest tenth, the volume of the paint bucket is:

\[
\boxed{1714.6} \text{ inches}^3
\]