To find the probability that John makes all three free throws, we can use the fact that each free throw is an independent event. The probability of making a single free throw is 35%, which can be expressed as a decimal:
\[ P(\text{make one free throw}) = 0.35 \]
Since the free throws are independent, we multiply the probabilities of making each free throw together:
\[ P(\text{make all three free throws}) = P(\text{make first}) \times P(\text{make second}) \times P(\text{make third}) \]
This becomes:
\[ P(\text{make all three free throws}) = 0.35 \times 0.35 \times 0.35 \]
Calculating this gives:
\[ P(\text{make all three free throws}) = 0.35^3 \]
Calculating \(0.35^3\):
\[ 0.35^3 = 0.042875 \]
To express this as a percentage, we multiply by 100:
\[ 0.042875 \times 100 = 4.2875 \]
Thus, the percent chance that John makes all three free throws is:
\[ \boxed{4.2875} \]