Question
Solve the following linear equation. Click Here for Help Video
John has to make all 3 free throws to win the game. Assume each free throw is an independent event and that the pressure of the situation has no impact on him. If John is a
35
35% free throw shooter what is the percent chance that John makes all three free throws? Do not round your answer
x=x=x=
Answers
GPT-4o mini
To find the probability that John makes all three free throws, we can use the fact that each free throw is an independent event. The probability of making a single free throw is 35%, which can be expressed as a decimal:
\[
P(\text{make one free throw}) = 0.35
\]
Since the free throws are independent, we multiply the probabilities of making each free throw together:
\[
P(\text{make all three free throws}) = P(\text{make first}) \times P(\text{make second}) \times P(\text{make third})
\]
This becomes:
\[
P(\text{make all three free throws}) = 0.35 \times 0.35 \times 0.35
\]
Calculating this gives:
\[
P(\text{make all three free throws}) = 0.35^3
\]
Calculating \(0.35^3\):
\[
0.35^3 = 0.042875
\]
To express this as a percentage, we multiply by 100:
\[
0.042875 \times 100 = 4.2875
\]
Thus, the percent chance that John makes all three free throws is:
\[
\boxed{4.2875}
\]
\[
P(\text{make one free throw}) = 0.35
\]
Since the free throws are independent, we multiply the probabilities of making each free throw together:
\[
P(\text{make all three free throws}) = P(\text{make first}) \times P(\text{make second}) \times P(\text{make third})
\]
This becomes:
\[
P(\text{make all three free throws}) = 0.35 \times 0.35 \times 0.35
\]
Calculating this gives:
\[
P(\text{make all three free throws}) = 0.35^3
\]
Calculating \(0.35^3\):
\[
0.35^3 = 0.042875
\]
To express this as a percentage, we multiply by 100:
\[
0.042875 \times 100 = 4.2875
\]
Thus, the percent chance that John makes all three free throws is:
\[
\boxed{4.2875}
\]