A jar contains jelly beans. There are

9 red jelly beans,
10 blue jelly beans and
7 green jelly beans. You randomly take two jelly beans out to eat. What is the probability that both are blue? Write your answer as a fraction. You do not need to simplif

1 answer

To calculate the probability that both jelly beans drawn are blue, we need to first determine the total number of jelly beans and then find the number of ways to choose 2 blue jelly beans from the total.

  1. Total number of jelly beans:

    • Red: 9
    • Blue: 10
    • Green: 7
    • Total = 9 + 10 + 7 = 26 jelly beans
  2. Number of ways to choose 2 jelly beans from the total:
    We can calculate this using the combination formula \(\binom{n}{r}\), which represents the number of ways to choose \(r\) objects from \(n\).
    \[ \text{Total ways to choose 2 jelly beans} = \binom{26}{2} = \frac{26 \times 25}{2 \times 1} = 325 \]

  3. Number of ways to choose 2 blue jelly beans:
    Using the same combination formula, we find: \[ \text{Ways to choose 2 blue jelly beans} = \binom{10}{2} = \frac{10 \times 9}{2 \times 1} = 45 \]

  4. Probability that both jelly beans drawn are blue:
    The probability \(P\) is given by the formula: \[ P(\text{both blue}) = \frac{\text{Number of ways to choose 2 blue}}{\text{Total ways to choose 2}} = \frac{45}{325} \]

Thus, the probability that both jelly beans drawn are blue is:

\[ \frac{45}{325} \]