Question
Chelsea said any number that is multiplied by 2 ends in either 0,2,4,6 or 8 Madison said that her statement is false who is correct use the figures and words to explain your answer
Answers
GPT-4o mini
Chelsea's statement is correct. Any integer multiplied by 2 will always produce an even number, which by definition ends in one of the digits 0, 2, 4, 6, or 8.
To explain this more clearly, consider the following points:
1. **Understanding Even and Odd Numbers**:
- Even numbers are defined as integers that are divisible by 2.
- Even integers end in 0, 2, 4, 6, or 8.
- Odd integers are not divisible by 2 and end in 1, 3, 5, 7, or 9.
2. **Multiplication by 2**:
- When any integer (whether even or odd) is multiplied by 2, the result is always an even integer.
- For example:
- \(2 \times 1 = 2\) (ends in 2)
- \(2 \times 2 = 4\) (ends in 4)
- \(2 \times 3 = 6\) (ends in 6)
- \(2 \times 4 = 8\) (ends in 8)
- \(2 \times 5 = 10\) (ends in 0)
3. **Conclusion**:
- Since the product of any integer multiplied by 2 is guaranteed to be an even number, which only ends in 0, 2, 4, 6, or 8, Chelsea's statement holds true.
Therefore, **Chelsea is correct** in her assertion that any number that is multiplied by 2 ends in either 0, 2, 4, 6, or 8. Madison's contradiction is false.
To explain this more clearly, consider the following points:
1. **Understanding Even and Odd Numbers**:
- Even numbers are defined as integers that are divisible by 2.
- Even integers end in 0, 2, 4, 6, or 8.
- Odd integers are not divisible by 2 and end in 1, 3, 5, 7, or 9.
2. **Multiplication by 2**:
- When any integer (whether even or odd) is multiplied by 2, the result is always an even integer.
- For example:
- \(2 \times 1 = 2\) (ends in 2)
- \(2 \times 2 = 4\) (ends in 4)
- \(2 \times 3 = 6\) (ends in 6)
- \(2 \times 4 = 8\) (ends in 8)
- \(2 \times 5 = 10\) (ends in 0)
3. **Conclusion**:
- Since the product of any integer multiplied by 2 is guaranteed to be an even number, which only ends in 0, 2, 4, 6, or 8, Chelsea's statement holds true.
Therefore, **Chelsea is correct** in her assertion that any number that is multiplied by 2 ends in either 0, 2, 4, 6, or 8. Madison's contradiction is false.