To solve the equation \(4|x+10| - 12 = 36\), we first isolate the absolute value term.
-
Add 12 to both sides: \[ 4|x+10| = 36 + 12 \] \[ 4|x+10| = 48 \]
-
Divide both sides by 4: \[ |x+10| = \frac{48}{4} \] \[ |x+10| = 12 \]
Now we have the absolute value equation. This gives us two cases to solve:
Case 1: \[ x + 10 = 12 \] Subtract 10 from both sides: \[ x = 12 - 10 = 2 \]
Case 2: \[ x + 10 = -12 \] Subtract 10 from both sides: \[ x = -12 - 10 = -22 \]
Thus, the solutions to the equation \(4|x+10| - 12 = 36\) are \(x = 2\) and \(x = -22\).
The correct response is: \[ x = 2, -22 \]