Question

Factor the expression below.
x^2+12x+36
0(X+9)(X+4)
0(x- 6)(x-6)
0 (x+6)(x+6)
0 (x-9)(x-4)

Answer 1

To factor the expression \( x^2 + 12x + 36 \), we need to look for two numbers that multiply to \( 36 \) (the constant term) and add up to \( 12 \) (the coefficient of the linear term).

The numbers that meet these criteria are \( 6 \) and \( 6 \), since:

- \( 6 \times 6 = 36 \) (they multiply to \( 36 \))
- \( 6 + 6 = 12 \) (they add up to \( 12 \))

Thus, we can factor the expression as:

\[
(x + 6)(x + 6) \text{ or } (x + 6)^2
\]

So the correct factoring of the expression \( x^2 + 12x + 36 \) is:

\((x + 6)(x + 6)\)

Therefore, the answer from the options provided would be:

\(0 \, (x + 6)(x + 6)\) (It seems the options are not formatted correctly, but this is the correct factorization.)