To find the distance between the maple tree and the oak tree, we need to start by establishing the total distances given in the problem and then use those to deduce the distance in question.
Here are the details from the diagram:
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Distance from the start to the maple tree = 5 yards.
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Distance from the maple tree to the end = \(2/8\) and \(2/6\) yards.
First, let’s convert these distances into a more usable form:
- \(2/8 = 0.25\) yards
- \(2/6\) = approximately \(0.3333\) yards (which is \(1/3\) yards).
To combine these, we can add them because both distances from the maple tree to the end will determine how far the next trees are positioned.
- Total from the maple tree to the end:
- \[0.25 + 0.3333 \approx 0.5833\]
So the distance from the maple tree to the end combined is: \[0.5833 \text{ yards}\]
After this, we look at the other distances:
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Distance from the oak tree to the pine tree = \(11/6\) yards or approximately \(11 + 0.1667 = 11.1667\) yards.
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Distance from the pine tree to the end = \(7 + 5/6\) yards or \(7 + 0.8333 = 7.8333\) yards.
To find the total distance from the start to the end:
- Start to maple = 5 yards
- Maple to oak (let's call it \(D\))
- Oak to pine (11 and three-sixths or approximately 11.5)
- Pine to end (7 and five-sixths or approximately 7.8333)
The total distance can be expressed mathematically as: \[ 5 + D + 11.5 + 7.8333 = \text{total distance from start to end} \]
However, we need \( D \), which corresponds to the difference of distances covering a few portions. Let’s calculate:
- From the end, we can see that we need to find the placement of the maple tree regarding these trees:
Let’s reevaluate our approach:
- Find distance from start to end:
- From the distances:
- If we assume the end is at the distance covered by the addition of both sets, this can be calculated as:
- Thus: \[ 5 + D + 11 + 7.8333 = \text{Find how far this lasts}\] Since it wouldn’t logically add defying the lengths, we assume \(D\) to exist at around auguring towards it through previous relations stated.
By figuring out:
- If total from start to finish minus components already calculated, we obtain:
- Find \(D\): Hence: \[ 19.16667 - 5 - 11.16667 - 7.8333 = D \]
- Conclusively uncovering to point the distance key \(3.4/6 = 0.6667\) yards enclosing towards that.
Thus:
- Therefore, the answer is \(3.4/6\) adhering towards the yard distance class defined.
Final answer: 3.4/6 yards.