To determine which of the numbers 1, 2, and 3 is a solution to the inequality \(2x + 1 \geq 7\), we can substitute each number into the inequality and see if it holds true.
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For \(x = 1\): \[ 2(1) + 1 = 2 + 1 = 3 \] Since \(3 \geq 7\) is false, 1 is not a solution.
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For \(x = 2\): \[ 2(2) + 1 = 4 + 1 = 5 \] Since \(5 \geq 7\) is false, 2 is not a solution.
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For \(x = 3\): \[ 2(3) + 1 = 6 + 1 = 7 \] Since \(7 \geq 7\) is true, 3 is a solution.
Thus, the solution to the inequality \(2x + 1 \geq 7\) among the numbers 1, 2, and 3 is 3.