Question
What is the force exerted on the lower arm to hold a 75 kg shot put in a horizontal position?
Answers
GPT-4o mini
To calculate the force exerted on the lower arm to hold a 75 kg shot put in a horizontal position, we need to consider the weight of the shot put and how this weight is balanced by the force exerted by the muscles in the arm.
First, we need to calculate the gravitational force (weight) acting on the shot put. The weight (W) can be calculated using the formula:
\[ W = m \cdot g \]
where:
- \( m \) is the mass of the shot put (75 kg),
- \( g \) is the acceleration due to gravity (approximately \( 9.81 \, \text{m/s}^2 \)).
Now, substituting the values:
\[ W = 75 \, \text{kg} \cdot 9.81 \, \text{m/s}^2 \]
\[ W = 735.75 \, \text{N} \]
Thus, the force exerted on the lower arm to hold the shot put in a horizontal position is **735.75 N** acting upward to counteract the weight of the shot put.
First, we need to calculate the gravitational force (weight) acting on the shot put. The weight (W) can be calculated using the formula:
\[ W = m \cdot g \]
where:
- \( m \) is the mass of the shot put (75 kg),
- \( g \) is the acceleration due to gravity (approximately \( 9.81 \, \text{m/s}^2 \)).
Now, substituting the values:
\[ W = 75 \, \text{kg} \cdot 9.81 \, \text{m/s}^2 \]
\[ W = 735.75 \, \text{N} \]
Thus, the force exerted on the lower arm to hold the shot put in a horizontal position is **735.75 N** acting upward to counteract the weight of the shot put.