To find the surface area of a right circular cylinder, we can use the formula:
\[ \text{Surface Area} = 2\pi r^2 + 2\pi rh \]
where:
- \( r \) is the radius of the base of the cylinder,
- \( h \) is the height (or length) of the cylinder.
First, we need to calculate the radius of the cylinder. The diameter is given as 0.50 inches, so the radius \( r \) is:
\[ r = \frac{\text{diameter}}{2} = \frac{0.50}{2} = 0.25 \text{ inches} \]
The length \( h \) is given as 36 inches.
Now we substitute these values into the surface area formula:
- Calculate the area of the two circular bases:
\[ 2\pi r^2 = 2 \times 3.14 \times (0.25)^2 = 2 \times 3.14 \times 0.0625 = 0.3925 \text{ inches}^2 \]
- Calculate the lateral surface area:
\[ 2\pi rh = 2 \times 3.14 \times 0.25 \times 36 = 2 \times 3.14 \times 9 = 56.52 \text{ inches}^2 \]
- Add both areas together to find the total surface area:
\[ \text{Surface Area} = 0.3925 + 56.52 \approx 56.9125 \text{ inches}^2 \]
Rounding this to two decimal places, we find:
\[ \text{Surface Area} \approx 56.91 \text{ inches}^2 \]
Thus, the correct response is:
56.91 inches² (or 56.91 inches squared)