you find that it takes a horizontal force of 160 newtons to slide a box along the surface of a level floor at constant speed . the coefficient of static friction is 0.52, and the coefficient of kinetic friction is 0.47. if you place the box on a dolly of mass 5.3 kg and with coefficient of rolling friction 0.018, what horizontal acceleration would that 160 newtons force provide?

asked by oslec

14 years ago

1,408 views

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1 answer

Let M be the mass of the box.

160=M*.47g so you have M.

160=(M+5.3)g*.018)a
solve for a.

answered by bobpursley

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2

Question

you find that it takes a horizontal force of 160 newtons to slide a box along the surface of a level floor at constant speed . the coefficient of static friction is 0.52, and the coefficient of kinetic friction is 0.47. if you place the box on a dolly of mass 5.3 kg and with coefficient of rolling friction 0.018, what horizontal acceleration would that 160 newtons force provide?

1 answer

Let M be the mass of the box.

160=M*.47g so you have M.

160=(M+5.3)g*.018)a
solve for a.

bobpursley · Answer

Let M be the mass of the box. 160=M*.47g so you have M. 160=(M+5.3)g*.018)a solve for a.