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A coordinate plane of 4 quadrants shows x and y axes ranging from negative 3 to 3 in increments of 1. A line with arrows at each end intercepts two plotted points, A and B. Point A is plotted at left parenthesis negative 2 comma 0 right parenthesis. Point B is plotted at left parenthesis 0 comma negative 1 right parenthesis. The coordinates are not labeled.
Which of the following is the equation of the line on the graph?
(1 point)
Responses
y=−2x−1
y equals negative 2 x minus 1
y=−12x−2
y equals negative Start Fraction 1 over 2 End Fraction x minus 2
y=−12x−1
y equals negative Start Fraction 1 over 2 End Fraction x minus 1
y=12x−1
y equals Start Fraction 1 over 2 End Fraction x minus 1
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A coordinate plane of 4 quadrants shows x and y axes ranging from negative 3 to 3 in increments of 1. A line with arrows at each end intercepts two plotted points, A and B. Point A is plotted at left parenthesis negative 2 comma 0 right parenthesis. Point B is plotted at left parenthesis 0 comma negative 1 right parenthesis. The coordinates are not labeled.
Which of the following is the equation of the line on the graph?
(1 point)
Responses
y=−2x−1
y equals negative 2 x minus 1
y=−12x−2
y equals negative Start Fraction 1 over 2 End Fraction x minus 2
y=−12x−1
y equals negative Start Fraction 1 over 2 End Fraction x minus 1
y=12x−1
y equals Start Fraction 1 over 2 End Fraction x minus 1
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Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the equation of the line that passes through the points A(-2, 0) and B(0, -1), we first need to find the slope (m) using the formula:
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
Taking the coordinates of point A as (x1, y1) = (-2, 0) and point B as (x2, y2) = (0, -1), we plug in the values:
\[
m = \frac{-1 - 0}{0 - (-2)} = \frac{-1}{2}
\]
The slope (m) is \(-\frac{1}{2}\). Now, we can use the point-slope form of the equation of a line:
\[
y - y_1 = m(x - x_1)
\]
Using point A (-2, 0) for (x1, y1):
\[
y - 0 = -\frac{1}{2}(x - (-2))
\]
This simplifies to:
\[
y = -\frac{1}{2}(x + 2)
\]
Distributing:
\[
y = -\frac{1}{2}x - 1
\]
Now, we can also rearrange this to the form:
\[
y = -\frac{1}{2}x - 1
\]
This matches with one of the given options:
**y = -\frac{1}{2} x - 1** (Option 3)
Thus, the correct answer is:
**y=−12x−1**
y equals negative Start Fraction 1 over 2 End Fraction x minus 1
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
Taking the coordinates of point A as (x1, y1) = (-2, 0) and point B as (x2, y2) = (0, -1), we plug in the values:
\[
m = \frac{-1 - 0}{0 - (-2)} = \frac{-1}{2}
\]
The slope (m) is \(-\frac{1}{2}\). Now, we can use the point-slope form of the equation of a line:
\[
y - y_1 = m(x - x_1)
\]
Using point A (-2, 0) for (x1, y1):
\[
y - 0 = -\frac{1}{2}(x - (-2))
\]
This simplifies to:
\[
y = -\frac{1}{2}(x + 2)
\]
Distributing:
\[
y = -\frac{1}{2}x - 1
\]
Now, we can also rearrange this to the form:
\[
y = -\frac{1}{2}x - 1
\]
This matches with one of the given options:
**y = -\frac{1}{2} x - 1** (Option 3)
Thus, the correct answer is:
**y=−12x−1**
y equals negative Start Fraction 1 over 2 End Fraction x minus 1
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