Question
Use the fact that 144 is a perfect square to evaluate StartRoot 144 EndRoot.
Question content area bottom
Part 1
StartRoot 144 EndRootequalsStartRoot left parenthesis plus or minus nothing right parenthesis squared EndRoot
Question content area bottom
Part 1
StartRoot 144 EndRootequalsStartRoot left parenthesis plus or minus nothing right parenthesis squared EndRoot
Answers
GPT-4o mini
To evaluate \(\sqrt{144}\), we can use the fact that \(144\) is a perfect square. Specifically, \(144 = 12^2\).
Thus, we can write:
\[
\sqrt{144} = \sqrt{12^2}
\]
By the property of square roots, we have:
\[
\sqrt{a^2} = |a|
\]
So,
\[
\sqrt{12^2} = |12| = 12
\]
Therefore,
\[
\sqrt{144} = 12
\]
In part 1, as mentioned, we can express this as:
\[
\sqrt{144} = \sqrt{(12)^2}
\]
or you could also express \(144\) in terms of \((\pm 12)^2\):
\[
\sqrt{144} = \sqrt{(\pm 12)^2} = |\pm 12| = 12
\]
Thus, we confirm:
\[
\sqrt{144} = 12
\]
Thus, we can write:
\[
\sqrt{144} = \sqrt{12^2}
\]
By the property of square roots, we have:
\[
\sqrt{a^2} = |a|
\]
So,
\[
\sqrt{12^2} = |12| = 12
\]
Therefore,
\[
\sqrt{144} = 12
\]
In part 1, as mentioned, we can express this as:
\[
\sqrt{144} = \sqrt{(12)^2}
\]
or you could also express \(144\) in terms of \((\pm 12)^2\):
\[
\sqrt{144} = \sqrt{(\pm 12)^2} = |\pm 12| = 12
\]
Thus, we confirm:
\[
\sqrt{144} = 12
\]