Question
What is the value of coefficient 'a' in the quadratic equation 4t^2 + 4t + 1 = 0?
Answers
GPT-4o mini
In the standard form of a quadratic equation, which is given by:
\[ at^2 + bt + c = 0, \]
the coefficients are represented as follows:
- \( a \) is the coefficient of \( t^2 \),
- \( b \) is the coefficient of \( t \),
- \( c \) is the constant term.
In the quadratic equation provided:
\[ 4t^2 + 4t + 1 = 0, \]
we can identify the coefficients:
- \( a = 4 \)
- \( b = 4 \)
- \( c = 1 \)
Thus, the value of the coefficient \( a \) is:
\[
\boxed{4}
\]
\[ at^2 + bt + c = 0, \]
the coefficients are represented as follows:
- \( a \) is the coefficient of \( t^2 \),
- \( b \) is the coefficient of \( t \),
- \( c \) is the constant term.
In the quadratic equation provided:
\[ 4t^2 + 4t + 1 = 0, \]
we can identify the coefficients:
- \( a = 4 \)
- \( b = 4 \)
- \( c = 1 \)
Thus, the value of the coefficient \( a \) is:
\[
\boxed{4}
\]