Asked by Jin
In the theory of relativity, the mass of a particle with velocity v is
m=mo/(square root ((1- v^ 2)/ c^2))
where mo is the mass of the particle at rest and ci s the speed of light. What happens as v goes to c?
m=mo/(square root ((1- v^ 2)/ c^2))
where mo is the mass of the particle at rest and ci s the speed of light. What happens as v goes to c?
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