Question
In the theory of relativity, the mass of a particle with velocity v is
m=mo/(square root ((1- v^ 2)/ c^2))
where mo is the mass of the particle at rest and ci s the speed of light. What happens as v goes to c?
m=mo/(square root ((1- v^ 2)/ c^2))
where mo is the mass of the particle at rest and ci s the speed of light. What happens as v goes to c?
Answers
i meant
what happens as v goes to c-
what happens as v goes to c-
as v goes to c, v^2 becomes c^2 and c^2/c^2 = 1,, therefore m becomes mo/sqrt(1-1) or mo/0 which is undefined,,
according to this, no such thing can exist with speed equal to the speed of light,,
so there,, =)
according to this, no such thing can exist with speed equal to the speed of light,,
so there,, =)
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