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Doreen had some packets of crackers she gave away 5/8 of them she gave away 15 packets of crackers how many packets of crackers did she have at first

5/9 of David sweets are red and the rest are green David has 15 red sweets does he have altogether

1 answer

Let's solve each part of the question one at a time.

Part 1: Doreen's Packets of Crackers

Doreen gave away \( \frac{5}{8} \) of her crackers, which equaled 15 packets. We can set up the equation as follows:

\[ \frac{5}{8} \times x = 15 \]

where \( x \) is the total number of packets of crackers Doreen had at first. To find \( x \), we first solve for \( x \):

  1. Multiply both sides by \( \frac{8}{5} \) to isolate \( x \):

\[ x = 15 \times \frac{8}{5} \]

  1. Calculate the right side:

\[ x = 15 \times \frac{8}{5} = 15 \times 1.6 = 24 \]

So, Doreen had 24 packets of crackers at first.

Part 2: David's Sweets

David has \( \frac{5}{9} \) of his sweets as red, and we know he has 15 red sweets. We can set up the equation:

Let \( y \) be the total number of sweets David has. Then:

\[ \frac{5}{9} y = 15 \]

To find \( y \), multiply both sides by \( \frac{9}{5} \):

\[ y = 15 \times \frac{9}{5} \]

Next, calculate:

\[ y = 15 \times 1.8 = 27 \]

Thus, David has 27 sweets altogether.

Summary

  • Doreen had 24 packets of crackers at first.
  • David has 27 sweets altogether.