Question

Doreen had some packets of crackers she gave away 5/8 of them she gave away 15 packets of crackers how many packets of crackers did she have at first

5/9 of David sweets are red and the rest are green David has 15 red sweets does he have altogether

Answer 1

Let's solve each part of the question one at a time.

### Part 1: Doreen's Packets of Crackers

Doreen gave away \( \frac{5}{8} \) of her crackers, which equaled 15 packets. We can set up the equation as follows:

\[
\frac{5}{8} \times x = 15
\]

where \( x \) is the total number of packets of crackers Doreen had at first. To find \( x \), we first solve for \( x \):

1. Multiply both sides by \( \frac{8}{5} \) to isolate \( x \):

\[
x = 15 \times \frac{8}{5}
\]

2. Calculate the right side:

\[
x = 15 \times \frac{8}{5} = 15 \times 1.6 = 24
\]

So, Doreen had **24 packets of crackers** at first.

### Part 2: David's Sweets

David has \( \frac{5}{9} \) of his sweets as red, and we know he has 15 red sweets. We can set up the equation:

Let \( y \) be the total number of sweets David has. Then:

\[
\frac{5}{9} y = 15
\]

To find \( y \), multiply both sides by \( \frac{9}{5} \):

\[
y = 15 \times \frac{9}{5}
\]

Next, calculate:

\[
y = 15 \times 1.8 = 27
\]

Thus, David has **27 sweets** altogether.

### Summary

- Doreen had 24 packets of crackers at first.
- David has 27 sweets altogether.