Question
Bryan has some marbles 3/5 of the marbles are blue he has 24 blue marbles how many marbles does he gave altogether
5/6 of a wire 10m long what length of whole wire
5/6 of a wire 10m long what length of whole wire
Answers
Answered by
GPT-4o mini
To find out how many marbles Bryan has altogether, we can set up the following equation based on the information given:
Let \( x \) be the total number of marbles. According to the problem, \( \frac{3}{5} \) of the marbles are blue, and we know he has 24 blue marbles. So we can write the equation:
\[
\frac{3}{5}x = 24
\]
To solve for \( x \), multiply both sides by \( \frac{5}{3} \):
\[
x = 24 \times \frac{5}{3}
\]
\[
x = 24 \times \frac{5}{3} = 24 \times 1.6667 = 40
\]
So, Bryan has **40 marbles altogether**.
---
For the second part of your question regarding the wire:
You mentioned that \( \frac{5}{6} \) of a wire is 10 meters long. To find the total length of the whole wire, we can set up the equation:
Let \( y \) be the total length of the wire. Then we can write:
\[
\frac{5}{6}y = 10
\]
To solve for \( y \), multiply both sides by \( \frac{6}{5} \):
\[
y = 10 \times \frac{6}{5}
\]
\[
y = 10 \times 1.2 = 12
\]
Thus, the **total length of the whole wire is 12 meters**.
Let \( x \) be the total number of marbles. According to the problem, \( \frac{3}{5} \) of the marbles are blue, and we know he has 24 blue marbles. So we can write the equation:
\[
\frac{3}{5}x = 24
\]
To solve for \( x \), multiply both sides by \( \frac{5}{3} \):
\[
x = 24 \times \frac{5}{3}
\]
\[
x = 24 \times \frac{5}{3} = 24 \times 1.6667 = 40
\]
So, Bryan has **40 marbles altogether**.
---
For the second part of your question regarding the wire:
You mentioned that \( \frac{5}{6} \) of a wire is 10 meters long. To find the total length of the whole wire, we can set up the equation:
Let \( y \) be the total length of the wire. Then we can write:
\[
\frac{5}{6}y = 10
\]
To solve for \( y \), multiply both sides by \( \frac{6}{5} \):
\[
y = 10 \times \frac{6}{5}
\]
\[
y = 10 \times 1.2 = 12
\]
Thus, the **total length of the whole wire is 12 meters**.